Question

How do you solve the following linear system: #y = 4x - 13 , y = 1/2x - 3/2 #?

Answer 1

`(23/7, 1/7) in mathbb{Q times Q}`

Explanation:

`y = 4x - 13 = 1/2 x - 3/2` // times two

`2y = 8x- 26 = x - 3`

`8x -x = -3 + 26`

`x = 23/7`

`y = 4 cdot 23/7 - 13`