How do you solve the following quadratic equation #3x^2 -12x =0#? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer Binayaka C. Jul 18, 2017 Solution : #x=0 or x=4# Explanation: #3 x^2-12x=0 or 3x(x-4)=0 or x(x-4)=0# #:. x=0 or x-4=0 :. x=4# Solution : #x=0 or x=4# [Ans] Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve #-3x^2+12x+1=0#? How do you solve #-4x^2+4x=9#? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation #81x^2+1=0#? How do you solve #-4x^2+4000x=0#? How do you solve for x in #x^2-6x+4=0#? How do you solve #x^2-6x-16=0# by factoring? How do you solve by factoring and using the principle of zero products #x^2 + 7x + 6 = 0#? How do you solve #x^2=2x#? See all questions in Comparing Methods for Solving Quadratics Impact of this question 1365 views around the world You can reuse this answer Creative Commons License