How do you solve the following system: $11 y + 3 x = 4, x - 2 y = 3$ $11y + 3x = 4, x-2y=3$ ?

Question

2305 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-07-17T08:28:56

$x = \frac{41}{17}$ $x = 41/17$
$y = - \frac{5}{17}$ $y = -5/17$

Let,
$3 x + 11 y = 4$ $3x + 11y = 4$ be eq 1
$x - 2 y = 3$ $x - 2y = 3$ be eq 2

now, multiply eq 2 by -3 so as it will be cancelled out in the next step.
we get,
$- 3 x + 6 y = - 9$ $-3x + 6y = -9$

$\Rightarrow 3 x + 11 y = 4$ $rArr 3x + 11y =4$
$- 3 x + 6 y = - 9$ $-3x + 6y = -9$

$\Rightarrow 17 y = - 5$ $rArr 17y = -5$
$therefore y =-5/17$
now, substitute value of y in any equation,
u get $x = 41/17$

ENJOY MATHS !!!!!

Answer 2 · 2017-07-17T08:30:34

By arranging equation, $x=41/17$ and $y=-5/17$

$3x + 11y = 4$
$-3x + 6y = -9$ (when you enlarge the second equation with -3)
Combine these two equations and get
$17y = -5$

$y = -5/17$

Put this value in any original equation (for instance the first)

$3x - 55/17 = 4$

$3x = (68+55)/17$

$x = 123/51$

$x= 41/17$

This is your answer $x=41/17$ and $y=-5/17$

How do you solve the following system: 11y + 3x = 4, x-2y=3 11y+3x=4,x−2y=311y + 3x = 4, x-2y=3 ?