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How do you solve the following system?: $- 2 x + 1 = 1, - x + y = - 3$ $-2x+1=1, -x+y=-3$

1 Answer

Jul 28, 2016

$x = 0$ $x=0$
$y = - 3$ $y=-3$

Explanation:

$- 2 x + 1 = 1$ $-2x+1=1$
or
$- 2 x = 1 - 1 = 0$ $-2x=1-1=0$
or
$2 x = 0$ $2x=0$
or
$x = 0$ $x=0$

$- x + y = - 3$ $-x+y=-3$

Putting vale of $x = 0$ $x=0$ in the above equatio we get
$- 0 + y = - 3$ $-0+y=-3$
or
$y = - 3$ $y=-3$

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