How do you solve the following system?: $- 2 x + 12 y = - 20, x - 5 y = 15$ $-2x+12y=-20 , x-5y=15$

Question

1520 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-04-19T05:41:18

The solution for the system of equations is:
$x = 40$ $color(green)(x=40$
$y = 5$ $color(green)(y= 5$

$- 2 x + 12 y = - 20$ $color(green)(- 2x) + 12 y = -20$ ..........equation $(1)$ $(1)$

$x - 5 y = 15$ $x - 5y = 15$ , multiplying by $2$ $2$
$2 x - 10 y = 30$ $color(green)(2x) - 10y = 30$ ....................equation $(2)$ $(2)$

Solving by elimination.

Adding equations $1$ $1$ and $2$ $2$ eliminates $2 x$ $2x$

$cancel color(green)(- 2x) + 12 y = -20$
$cancelcolor(green)(2x) - 10y = 30$

$2y = 10$

$y = 10/2$

$color(green)(y= 5$

Finding $x$ from the second equation provided:

$color(blue)(x) - 5y = 15$

$x = 15+ 5y$

$x = 15+ 5 * color(green)(5$

$x = 15+ 25$

$color(green)(x=40$

How do you solve the following system?: -2x+12y=-20 , x-5y=15 −2x+12y=−20,x−5y=15-2x+12y=-20 , x-5y=15