How do you solve the following system?: $- 2 x + 3 y = 5, 3 x + 2 y = 12$ $-2x+3y=5, 3x+2y=12$

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Answer 1 · 2017-04-02T13:31:01

$y = 3, x = 2$ $color(red)(y=3,x=2$

$:.-2x+3y=5$ -----(1)

$:.3x+2y=12$ --------(2)

$:.(2) xx 3$

$:.9x+6y=36$ --------(3)

$:.(1) xx 2$

$:.-4x+6y=10$ ------(4)

$:.(3) -(4)$

$:.13x=26$

$:.color(red)(x=2$

Substitute x=2 in (2)

$:.3(2)+2y=12$

$:.6+2y=12$

$:.2y=12-6$

$:.2y=6$

$:.color(red)(y=3$

Substitute $y=3,x=2$ in (1)

$:.-2(2)+3(3)=5$

$:.-4+9=5$

$:.color(red)(5=5$

How do you solve the following system?: -2x+3y=5, 3x+2y=12 −2x+3y=5,3x+2y=12 -2x+3y=5, 3x+2y=12