How do you solve the following system?: $- 2 x - 5 y = 13, 3 x - 6 y = - 4$ $-2x -5y =13, 3x -6y = -4$

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Answer 1 · 2018-05-20T21:11:59

$x = - \frac{98}{27}$ $x=-98/27$ and $y = - \frac{31}{27}$ $y=-31/27$

$3 \cdot (- 2 x - 5 y) + 2 \cdot (3 x - 6 y) = 3 \cdot 13 + 2 \cdot (- 4)$ $3*(-2x-5y)+2*(3x-6y)=3*13+2*(-4)$

$- 6 x - 15 y + 6 x - 12 y = 39 - 8$ $-6x-15y+6x-12y=39-8$

$- 27 y = 31$ $-27y=31$ , so $y = \frac{31}{- 27} = - \frac{31}{27}$ $y=31/(-27)=-31/27$

Thus,

$- 2 x - 5 \cdot (- \frac{31}{27}) = 13$ $-2x-5*(-31/27)=13$

$- 2 x + \frac{155}{27} = 13$ $-2x+155/27=13$

$- 2 x = \frac{196}{27}$ $-2x=196/27$ or $x = \frac{\frac{196}{17}}{- 2} = - \frac{98}{27}$ $x=(196/17)/(-2)=-98/27$

How do you solve the following system?: −2x−5y=13,3x−6y=−4-2x -5y =13, 3x -6y = -4