Question

How do you solve the following system: `2x-5y=-19, y + 4x = 16`?

Answer 1

`x=3 17/22` and `y=4 10/11`

Explanation:

Putting value of `y` from `y+4x=16` i.e. `y=16-4x` in `2x-5y=-19`, we get

`2x-5(16-4x)=-19` or

`2x-80+20x=-19` or

`22x=80-19=61` or `x=61/22=3 17/22`

Now putting this in `y=16-4x` we get `y=16-(4xx61)/22` or

`y=16-244/22=16-11 2/22=4 20/22=4 10/11`