How do you solve the following system: 2x+7y=1, 5x - 7y = 12 2x+7y=1,5x7y=12?

1 Answer
Aug 13, 2017

See a solution process below:

Explanation:

Step 1) Solve each equation for 7y7y:

Equation 1:

2x + 7y = 12x+7y=1

-color(red)(2x) + 2x + 7y = -color(red)(2x) + 12x+2x+7y=2x+1

0 + 7y = -2x + 10+7y=2x+1

7y = -2x + 17y=2x+1

Equation 2:

5x - 7y = 125x7y=12

-color(red)(5x) + 5x - 7y = -color(red)(5x) + 125x+5x7y=5x+12

0 - 7y = -5x + 1207y=5x+12

-7y = -5x + 127y=5x+12

color(red)(-1) xx -7y = color(red)(-1)(-5x + 12)1×7y=1(5x+12)

7y = 5x - 127y=5x12

Step 2) Because the left side of each equation is 7y7y we can equate the right side of each equation and solve for xx:

-2x + 1 = 5x - 122x+1=5x12

color(red)(2x) - 2x + 1 + color(blue)(12) = color(red)(2x) + 5x - 12 + color(blue)(12)2x2x+1+12=2x+5x12+12

0 + 13 = (color(red)(2) + 5)x - 00+13=(2+5)x0

13 = 7x13=7x

13/color(red)(7) = (7x)/color(red)(7)137=7x7

13/7 = (color(red)(cancel(color(black)(7)))x)/cancel(color(red)(7))

13/7 = x

x = 13/7

*Step 3) Substitute 13/7 for x in the solution to either equation in Step 1 and calculate y:

7y = -2x + 1 becomes:

7y = (-2 xx 13/7) + 1

7y = -26/7 + 1

7y = -26/7 + (7/7 xx 1)

7y = -26/7 + 7/7

7y = -19/7

(7y)/color(red)(7) = (-19/7)/color(red)(7)

(color(red)(cancel(color(black)(7)))y)/cancel(color(red)(7)) = -19/49

y = -19/49

The Solution Is: x = 13/7 and y = -19/49 or (13/7, -19/49)