How do you solve the following system: $2 x + y = 5, 5 x + 2 y = 12$ $2x+y=5, 5x+2y=12$ ?

Question

2417 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-03-26T02:13:40

$x = 2$ $x=2$
$y = 1$ $y=1$

Given -

$2 x + y = 5$ $2x+y=5$ ---------------(1)
$5 x + 2 y = 12$ $5x+2y=12$ -------------(2)

Solve equation (1) for $y$ $y$

$y = 5 - 2 x$ $y=5-2x$

Substitute $y = 5 - 2 x$ $y=5-2x$ in equation (2)

$5 x + 2 (5 - 2 x) = 12$ $5x+2(5-2x)=12$

Simplify and find the value of $x$ $x$

$5 x + 10 - 4 x = 12$ $5x+10-4x=12$
$x = 12 - 10$ $x=12-10$
$x = 2$ $x=2$

Substitute $x = 2$ $x=2$ in equation (1) and find the value of $y$ $y$

$2 (2) + y = 5$ $2(2)+y=5$
$4 + y = 5$ $4+y=5$
$y = 5 - 4$ $y=5-4$
$y = 1$ $y=1$
Watch this Video also

How do you solve the following system: 2x+y=5, 5x+2y=12 2x+y=5,5x+2y=122x+y=5, 5x+2y=12 ?