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How do you solve the following system: $3 x + 4 y = 11, - 6 x + 5 y = 4$ $3x + 4y = 11 , -6x + 5y = 4$ ?

1 Answer

May 30, 2018

$x = 1$ $x=1$ and $y = 2$ $y=2$

Explanation:

Multiplying the first equation by $2$ $2$ and adding to the second, we get

$13 y = 26$ $13y=26$
so

$y = 2$ $y=2$

then we get

$3 x + 8 = 11$ $3x+8=11$

so

$x = 1$ $x=1$

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