How do you solve the following system: $4 x + 3 y = 36, 4 x + 2 y = 10$ $4x+3y=36, 4x + 2y = 10$ ?

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Answer 1 · 2016-02-27T07:39:01

$(- 10.5, 26)$ $(-10.5,26)$

Given equations
$4 x + 3 y = 36$ $4x+3y=36$ ---------(1)
$4 x + 2 y = 10$ $4x+2y=10$ ---------(2)

Subtract equation 2 from equation 1

$y = 26$ $y=26$

Substitute in equation 1

$4 x + 3 y = 36$ $4x+3y=36$

$4 x + 3 (26) = 36$ $4x+3(26)=36$

$4 x + 78 = 36$ $4x+78=36$

$4 x = 36 - 78$ $4x=36-78$

$4 x = - 42$ $4x=-42$

$x = - \frac{42}{4}$ $x=-42/4$

$x = - 10.5$ $x=-10.5$

How do you solve the following system: 4x+3y=36,4x+2y=104x+3y=36, 4x + 2y = 10 ?