-4x- 3y = 5 - - - eqn1−4x−3y=5−−−eqn1
x - 2y = -15 - - - eqn2x−2y=−15−−−eqn2
From the eqn1eqn1 rearrange the equation..
-4x - 3y = 5−4x−3y=5
Multiplying through by minus(-)(−);
-(-4x - 3y = 5)−(−4x−3y=5)
4x + 3y = -5 - - - eqn14x+3y=−5−−−eqn1
Now solving simultaneously..
4x + 3y = -5 - - - eqn14x+3y=−5−−−eqn1
x - 2y = -15 - - - eqn2x−2y=−15−−−eqn2
Using Elimination Method..
Multiplying eqn1eqn1 by 11 and eqn2eqn2 by 44 respectively..
1(4x + 3y = -5)1(4x+3y=−5)
4(x - 2y = -15)4(x−2y=−15)
4x + 3y = -5 - - - eqn34x+3y=−5−−−eqn3
4x - 8y = -60 - - - eqn44x−8y=−60−−−eqn4
Subtracting eqn4eqn4 from eqn3eqn3
(4x - 4x) + (3y - (-8y) = -5 - (-60)(4x−4x)+(3y−(−8y)=−5−(−60)
0 + 3y + 8y = -5 + 600+3y+8y=−5+60
11y = 5511y=55
y = 55/11y=5511
y = 5y=5
Substituting the value of yy into eqn2eqn2
x - 2y = -15 - - - eqn2x−2y=−15−−−eqn2
x - 2(5) = -15x−2(5)=−15
x - 10 = -15x−10=−15
x = -15 + 10x=−15+10
x = -5x=−5
Therefore;
x = -5 and y = 5x=−5andy=5
