How do you solve the following system: 4x+y=1,5x7y=12?

1 Answer
Apr 13, 2018

x=533
y=53
(533,53)

Explanation:

4x+y=1, 5x7y=12
Take the first equation, 4x+y=1, and isolate y:
y=4x1. We can substitute this value into the second equation:
5x7(4x1)=12. Distribute the parentheses:
5x+28x+7=12 Combine like terms, isolate x and coeffecient:
33x=5 Isolate x:
x=533 Input this value into the first equation:
4(533)+y=1 Distribute y
2033+y=1 Isolate y
y=5533
y=53