How do you solve the following system?: 5x4y=3,3xy=2

1 Answer
Mar 2, 2017

x=1117 and y=117

Explanation:

5x4y=3
3xy=2

From the second equation, we can determine a temporary value for y.

3xy=2

Add y to each side.

3x=y2

Add 2 to each side.

3x+2=y

In the first equation, substitute y with (3x+2).

5x4y=3

5x4(3x+2)=3

Open the brackets ad simplify. The product of a negative and a positive is a negative.

5x12x8=3

17x8=3

Add 8 to each side.

17x=11

Divide both sides by 17.

x=1117

In the second equation, substitute x with (1117).

3xy=2

3(1117)y=2

Open the brackets and simplify. The product of a positive and a negative is a negative.

3317y=2

Add y to each side.

3317=y2

Add 2 to each side.

3317+2=y

3317+(2×1717)=y

3317+3417=y

33+3417=y

117=y