How do you solve the following system?: $5 x - 7 y = 22, 4 x - 3 y = 15$ $5x-7y=22 , 4x-3y=15$

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Answer 1 · 2017-11-26T16:59:29

$x = 3$ $x=3$ and $y = - 1$ $y=-1$

$7 \cdot (4 x - 3 y) - 3 \cdot (5 x - 7 y) = 15 \cdot 7 - 3 \cdot 22$ $7*(4x-3y)-3*(5x-7y)=15*7-3*22$

$(28 x - 21 y) - (15 x - 21 y) = 105 - 66$ $(28x-21y)-(15x-21y)=105-66$

$13 x = 39$ $13x=39$ , so $x = 3$ $x=3$

$5 \cdot 3 - 7 y = 22$ $5*3-7y=22$

$15 - 7 y = 22$ $15-7y=22$

$- 7 y = 7$ $-7y=7$ , so $y = - 1$ $y=-1$

How do you solve the following system?: 5x-7y=22 , 4x-3y=15 5x−7y=22,4x−3y=155x-7y=22 , 4x-3y=15