How do you solve the following system?: 6x−4y=3,5x−2y=1

1 Answer
Nallasivam V
Dec 2, 2015

x=−14
y=−98

Explanation:

6x−4y=3 --------------(1)
5x−2y=1 ------------------(2)
Let us have the equations as -

We are going to eliminate y

Before that understand −4y+4y=0

Multiply equation (2) with −2

6x−4y=3 ------------------(1)
−10x+4y=−2 ------------------(2)

Add (1) and (2), we get -

−4x=1
x=−14

Substitute x=−14 in equation (1)

6(−14)−4y=3
−64−4y=3
−32−4y=3
−4y=3+32=6+32=92
y=92×1−4=−98

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