How do you solve the following system?: $7 x + 4 y = 13, - 7 x - 2 y = - 2$ $7x +4y = 13 , -7x - 2y = -2$

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Answer 1 · 2018-04-30T08:02:03

By arranging the equations. Get $x = - \frac{9}{7}$ $x=-9/7$ and $y = \frac{11}{2}$ $y=11/2$

Add these:

$7 x + 4 y = 13$ $7x + 4y = 13$
$- 7 x - 2 y = - 2$ $-7x - 2y = -2$

$7 x - 7 x + 4 y - 2 y = 13 - 2$ $7x - 7x + 4y - 2y = 13-2$

$2 y = 11$ $2y = 11$

$y = \frac{11}{2}$ $y=11/2$

Put this value in the first equation:

$7 x + (4 \times \frac{11}{2}) = 13$ $7x + (4times11/2) = 13$

$7 x + 22 = 13$ $7x + 22 = 13$

$7 x = 13 - 22$ $7x = 13-22$

$7 x = - 9$ $7x = -9$

$x = - \frac{9}{7}$ $x = -9/7$

How do you solve the following system?: 7x+4y=13,−7x−2y=−27x +4y = 13 , -7x - 2y = -2