How do you solve the following system?: $7 y = 4 - 2 x, 2 x + y = - 8$ $7y=4- 2x , 2x + y = -8$

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Answer 1 · 2016-01-01T16:38:28

The solution for the system of equations is

$x = - 5, y = 2$ $color(blue)(x=-5,y=2$

$2 x + 7 y = 4$ $color(blue)(2x) +7y=4$ .........equation $(1)$ $(1)$

$2 x + y = - 8$ $color(blue)(2x) +y=-8$ .....equation $(2)$ $(2)$

Solving by elimination.

Subtracting $2$ $2$ from $1$ $1$ :

$2 x + 7 y = 4$ $color(blue)(2x) +7y=4$

$- 2 x - y = + 8$ $-color(blue)(2x) -y=+8$

$6 y = 12$ $6y=12$

$y = \frac{12}{6}$ $y=12/6$

$y = 2$ $color(blue)(y=2$

Finding $x$ $x$ from equation $1$ $1$

$2 x + 7 y = 4$ $2x +7y=4$

$2 x + 7 \times 2 = 4$ $2x +7 xx 2=4$

$2 x + 14 = 4$ $2x +14=4$

$2 x = 4 - 14$ $2x =4-14$

$2 x = - 10$ $2x =-10$

$x = - \frac{10}{2}$ $x=-10/2$

$x = - 5$ $color(blue)(x=-5$

How do you solve the following system?: 7y=4−2x,2x+y=−8 7y=4- 2x , 2x + y = -8