How do you solve the following system: 7y − 6x − 5 = 0, y + 4x = 16 7y6x5=0,y+4x=16?

1 Answer
May 21, 2017

See a solution process below:

Explanation:

Step 1) Solve the second equation for yy:

y + 4x = 16y+4x=16

y + 4x - color(red)(4x) = 16 - color(red)(4x)y+4x4x=164x

y + 0 = 16 - 4xy+0=164x

y = 16 - 4xy=164x

Step 2) Substitute (16 - 4x)(164x) for yy in the first equation and solve for xx:

7y - 6x - 5 = 07y6x5=0 becomes:

7(16 - 4x) - 6x - 5 = 07(164x)6x5=0

(7 * 16) - (7 * 4x) - 6x - 5 = 0(716)(74x)6x5=0

112 - 28x - 6x - 5 = 011228x6x5=0

112 - 5 - 28x - 6x = 0112528x6x=0

(112 - 5) + (-28 - 6)x = 0(1125)+(286)x=0

107 + (-34)x = 0107+(34)x=0

107 + (-34)x + color(red)(34x) = 0 + color(red)(34x)107+(34)x+34x=0+34x

107 + 0 = 34x107+0=34x

107 = 34x107=34x

107/color(red)(34) = (34x)/color(red)(34)10734=34x34

107/34 = (color(red)(cancel(color(black)(34)))x)/cancel(color(red)(34))

107/34 = x

x = 107/34

Step 3) Substitute 107/34 for x in the solution to the second equation at the end of Step 1 and calculate y:

y = 16 - 4x becomes:

y = 16 - (4 xx 107/34)

y = (34/34 xx 16) - 428/34

y = 544/34 - 428/34

y = 116/34

y = (2 xx 58)/(2 xx 17)

y = (color(red)(cancel(color(black)(2))) xx 58)/(color(red)(cancel(color(black)(2))) xx 17)

y = 58/17

The solution is: x = 107/34 and y = 58/17 or (107/34, 58/17)