How do you solve the following system: $8x - y = 13 , 5x+y=-7$ ?

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Answer 1 · 2018-04-29T10:22:39

Solution: $x=6/13, y = -9 4/13$

$8 x- y = 13 (1) ; 5 x+ y = -7 (2)$ Adding equations (1) and (2)

we get $13 x = 6 :. x = 6/13$ Putting $x= 6/13$ in equation (1)

we get , $8*6/13- y = 13 or y= 48/13-13 or y = (48-169)/13$ or

$y= -121/13 = -9 4/13$

Solution: $x=6/13, y = -9 4/13$ [Ans]

How do you solve the following system: 8x - y = 13 , 5x+y=-7 8x - y = 13 , 5x+y=-7 ?