Given
[1]color(white)("XXX")-9x-3y=2
[2]color(white)("XXX")3x-y=-1
Multiplying [2] by 3
color(white)("XXXX")3xx(3x-y)=3xx(-1)
[3]color(white)("XXX")9x-3y=-3
Adding [1] and [3]
color(white)("XXXX")-9x-3y=2
color(white)("XXXXX")underline(9x-3y)=underline(-3)
[4]color(white)("XXXXXX")-6y=-1
Dividing [4] by (-6)
color(white)("XXX")(cancel(-6)y)/cancel(-6)=(cancel(-)1)/(cancel(-)6)
[5]color(white)("XXX")y=1/6
Substituting (1/6) for y in [2]
[6]color(white)("XXX")3x-(1/6)=-1
Adding 1/6 to both sides of [6]
color(white)("XXX")3xcancel(-(1/6))cancel(+1/6)=-1+1/6
[7]color(white)("XXX")3x=-5/6
Dividing both sides of [7] by 3
color(white)("XXX")(cancel(3)x)/cancel(3)= -(5/6)/3
[8]color(white)("XXX")x=-5/18