How do you solve the following system of two equations in three variables given $x + 2 y + z = 4$ $x + 2y + z = 4$ and $3 x - y - 4 z = - 9$ $3x - y - 4z = -9$ ?

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How do you solve the following system of two equations in three variables given $x + 2 y + z = 4$ $x + 2y + z = 4$ and $3 x - y - 4 z = - 9$ $3x - y - 4z = -9$ ?

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Answer 1 · 2015-03-28T17:44:27

There is no complete solution. If you have $3$ $3$ variables you need $3$ $3$ restricting equations to (possibly) find fixed values for your variables.

At best, by combining these equations in the normal way, you could get
$x = z - 2$ $x=z-2$
and
$y = 3 - z$ $y= 3-z$

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How do you solve the following system of two equations in three variables given $x + 2 y + z = 4$ $x + 2y + z = 4$ and $3 x - y - 4 z = - 9$ $3x - y - 4z = -9$ ?

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How do you solve the following system of two equations in three variables given x+2y+z=4x + 2y + z = 4 and 3x−y−4z=−93x - y - 4z = -9?

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How do you solve the following system of two equations in three variables given $x + 2 y + z = 4$ $x + 2y + z = 4$ and $3 x - y - 4 z = - 9$ $3x - y - 4z = -9$ ?