How do you solve the following system using Cramer's rule $2x-y=3, 4x-3y=5$ ?

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Answer 1 · 2018-01-06T23:10:03

$P={(2,1)}$

$A=([2,-1,|,3],[4,-3,|,5])$

$D=detA=|[2,-1],[4,-3]|=2xx(-3)-(-1)xx4=-6+4=-2$

$D_1=|[3,-1],[5,-3]|=3xx(-3)-(-1)xx5=-9+5=-4$

$D_2=|[2,3],[4,5]|=2xx5-3xx4=10-12=-2$

$x=D_1/D=(-4)/-2=2$

$y=D_2/D=(-2)/-2=1$

$P={(2,1)}$

How do you solve the following system using Cramer's rule 2x-y=3, 4x-3y=52x-y=3, 4x-3y=5?