How do you solve the following system using substitution?: $7 x - y = 10 x = \frac{y}{3} - 2$ $7x-y=10 x=y/3-2$

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How do you solve the following system using substitution?: $7 x - y = 10 x = \frac{y}{3} - 2$ $7x-y=10 x=y/3-2$

1 Answer

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Answer 1 · 2018-05-26T17:39:33

$x = 4, y = 18$ $x=4,y=18$

Explanation:

From the second equation we get:
$7 (\frac{y}{3} - 2) - y = 10$ $7(y/3-2)-y=10$
$\frac{7}{3} y - y = 24$ $7/3y-y=24$
$\frac{7}{3} y - \frac{3}{3} y = 24$ $7/3y-3/3y=24$
$\frac{4}{3} y = 24$ $4/3y=24$
$y = 3 \cdot \frac{24}{4} = 18$ $y=3*24/4=18$
so
$x = \frac{18}{3} - 2 = 6 - 2 = 4$ $x=18/3-2=6-2=4$

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How do you solve the following system using substitution?: $7 x - y = 10 x = \frac{y}{3} - 2$ $7x-y=10 x=y/3-2$

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How do you solve the following system using substitution?: $7 x - y = 10 x = \frac{y}{3} - 2$ $7x-y=10 x=y/3-2$