How do you solve the following system: $x - 3 y = 20, - 6 x + 5 y = 4$ $x-3y=20 , -6x + 5y = 4$ ?

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Answer 1 · 2018-07-09T11:41:21

$x = 48.615384 and y = 9.5384$ $x= 48.615384 and y = 9.5384$

$x - 3 y = 20$ $x-3y=20$ ----------------(1)

$- 6 x + 5 y = 4$ $-6x + 5y = 4$ -----------------(2)

We can find the value off variable $x$ $x$ in terms of $y$ $y$ from equation (1) as the coefficient of $x$ $x$ is 1 .

$\Rightarrow x = 20 + 3 y$ $=> x= 20+3y$ ----------(3)

Now, substitute this value of $x$ $x$ in equation (2),

$\Rightarrow - 6 (20 + 3 y) + 5 y = 4$ $=> -6(20+3y) +5y = 4$

$\Rightarrow - 120 - 18 y + 5 y = 4$ $=> -120 - 18y +5y = 4$

$\Rightarrow - 18 y + 5 y = 4 + 120$ $=> -18y +5y = 4+120$

$\Rightarrow - 13 y = 124$ $=> -13y =124$

$therefore y= 124/-13 = 9.5384$ ------(4) --- (truncated value)

Now substitute this value of $y$ in equation (3) to get the value of $x$ ,

$=> x= 20 +3(9.5384) = 20 + 28.615384 = 48.615384$

$therefore x= 48.615384 and y = 9.5384$

Note: The values of $x$ and $y$ are truncated.

How do you solve the following system: x-3y=20 , -6x + 5y = 4 x−3y=20,−6x+5y=4x-3y=20 , -6x + 5y = 4 ?