How do you solve the following system?: $- x - 5 y = 3, x - 16 y = - 42$ $-x -5y =3, x -16y = -42$

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How do you solve the following system?: $- x - 5 y = 3, x - 16 y = - 42$ $-x -5y =3, x -16y = -42$

1 Answer

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Answer 1 · 2017-08-15T00:06:56

$y = \frac{13}{7}, x = - \frac{86}{7}$ $y = 13/7 , x = - 86/7$

Explanation:

Adding the equations eliminates ' x '
$- 21 y = - 39 \Rightarrow y = \frac{13}{7}$ $-21 y = - 39 => y = 13/7$
Substituting back
$x = - 5 y - 3 = - 5 (\frac{13}{7}) - (\frac{21}{7}) = - \frac{86}{7}$ $x = - 5y - 3 = - 5 (13/7) - (21/7) = - 86/7$

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How do you solve the following system?: $- x - 5 y = 3, x - 16 y = - 42$ $-x -5y =3, x -16y = -42$

1 Answer

Explanation:

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Science

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How do you solve the following system?: -x -5y =3, x -16y = -42−x−5y=3,x−16y=−42-x -5y =3, x -16y = -42

1 Answer

Explanation:

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How do you solve the following system?: $- x - 5 y = 3, x - 16 y = - 42$ $-x -5y =3, x -16y = -42$