How do you solve the following system?: $- x - 6 y = - 1, 3 x - y = - 4$ $-x -6y =-1, 3x -y = -4$

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How do you solve the following system?: $- x - 6 y = - 1, 3 x - y = - 4$ $-x -6y =-1, 3x -y = -4$

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Answer 1 · 2015-11-17T21:52:01

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Explanation:

Isolate one variable in one the equations. Then use the resulting equivalent to replace the same variable in the other equation

$- x - 6 y = - 1$ $-x - 6y = -1$
$3 x - y = - 4$ $3x - y = -4$

If we isolate $x$ $x$ in the first equation, we will have

$- x - 6 y = - 1$ $-x - 6y = -1$
$\Rightarrow x = - 6 y + 1$ $=> x = -6y + 1$

Now, let's replace $x$ $x$ in the second equation

$3 x - y = - 4$ $3x - y = -4$
$\Rightarrow 3 (- 6 y + 1) - y = - 4$ $=> 3(-6y + 1) - y = -4$
$\Rightarrow - 18 y + 3 - y = - 4$ $=> -18y + 3 - y = -4$
$\Rightarrow - 19 y + 3 = - 4$ $=> -19y + 3 = -4$
$\Rightarrow - 19 y = - 7$ $=> -19y = -7$
$\Rightarrow y = \frac{7}{19}$ $=> y = 7/19$

Now that we have the value for $y$ $y$ , substitute it into any of the equalities above to get $x$ $x$

$x = - 6 y + 1$ $x = -6y + 1$
$\Rightarrow x = - 6 (\frac{7}{19}) + 1$ $=> x = -6(7/19) + 1$
$\Rightarrow x = - \frac{42}{19} + 1$ $=> x = -42/19 + 1$

$\Rightarrow x = \frac{- 42 + 19}{19}$ $=> x = (-42 + 19)/19$

$\Rightarrow x = - \frac{23}{19}$ $=> x = -23/19$

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How do you solve the following system?: $- x - 6 y = - 1, 3 x - y = - 4$ $-x -6y =-1, 3x -y = -4$

1 Answer

Explanation:

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Impact of this question

Science

Math

Humanities

... and beyond

How do you solve the following system?: −x−6y=−1,3x−y=−4-x -6y =-1, 3x -y = -4

1 Answer

Explanation:

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Impact of this question

How do you solve the following system?: $- x - 6 y = - 1, 3 x - y = - 4$ $-x -6y =-1, 3x -y = -4$