How do you solve the following system?: $x + 6 y = 13, 4 x - 5 y = 5$ $x + 6y = 13 , 4x-5y=5$

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How do you solve the following system?: $x + 6 y = 13, 4 x - 5 y = 5$ $x + 6y = 13 , 4x-5y=5$

1 Answer

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Answer 1 · 2018-06-09T05:27:58

$x = \frac{95}{29}$ $x=95/29$
$y = \frac{47}{29}$ $y=47/29$

Explanation:

$x + 6 y = 13$ $x+6y=13$ --- (1)
$4 x - 5 y = 5$ $4x-5y=5$ --- (2)

From (1),
$x + 6 y = 13$ $x+6y=13$
$x = 13 - 6 y$ $x=13-6y$ --- (3)

Sub (3) into (2)
$4 (13 - 6 y) - 5 y = 5$ $4(13-6y)-5y=5$
$52 - 24 y - 5 y = 5$ $52-24y-5y=5$
$47 = 29 y$ $47=29y$
$y = \frac{47}{29}$ $y=47/29$ --- (4)

Sub (4) into (3)
$x = 13 - 6 y$ $x=13-6y$
$x = 13 - 6 (\frac{47}{29})$ $x=13-6(47/29)$
$x = \frac{95}{29}$ $x=95/29$

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How do you solve the following system?: $x + 6 y = 13, 4 x - 5 y = 5$ $x + 6y = 13 , 4x-5y=5$

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Explanation:

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How do you solve the following system?: x+6y=13,4x−5y=5 x + 6y = 13 , 4x-5y=5

1 Answer

Explanation:

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How do you solve the following system?: $x + 6 y = 13, 4 x - 5 y = 5$ $x + 6y = 13 , 4x-5y=5$