How do you solve the following system?: $x + 6 y = 13, 5 y = x + 10$ $x + 6y = 13 , 5y = x + 10$

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Answer 1 · 2018-03-11T14:30:31

$x = \frac{5}{11}, y = \frac{23}{11}$ $x = 5/11, y = 23/11$

$x + 6 y = 13$ $x + 6y = 13$ Eqn (1)

$5 y = x + 10$ $5y = x + 10$

$- x + 5 y = 10$ $-x + 5y = 10$ Eqn (2). Rearranging variables to L H S.

Adding Eqns (1), (2),

$6 y + 5 y = 23$ $6y + 5y = 23$ , $11 y = 23$ $11y = 23$

$y = \frac{23}{11}$ $y = 23/11$

Substituting value of y in Eqn (1),

$x + 6 \cdot (\frac{23}{11}) = 13$ $x + 6*(23/11) = 13$

$11 x + 138 = 143$ $11x + 138 = 143$

$11 x = - 138 + 143 = 5$ $11x = -138 + 143 = 5$

$x = \frac{5}{11}$ $x = 5/11$

How do you solve the following system?: x+6y=13,5y=x+10 x + 6y = 13 , 5y = x + 10