How do you solve the following system?: $- x - y = - 1, x - y = - 1$ $-x -y =-1, x -y = -1$

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Answer 1 · 2015-11-11T07:17:37

The solution for the system of equations is
$x = 0$ $color(blue)(x=0$
$y = 1$ $color(blue)(y=1$

$- x - y = - 1$ $color(blue)(−x)−y=−1$ ....equation $(1)$ $(1)$
$x - y = - 1$ $color(blue)(x)−y=−1$ .........equation $(2)$ $(2)$

Upon observing the two equations we realize that by adding them we can eliminate $x$ $color(blue)(x$

Solving by elimination

$cancelcolor(blue)(−x)−y=−1$
$cancelcolor(blue)(x)−y=−1$

$-2y=-2$

$y=(-2)/-2$

$color(blue)(y=1$

Now we find $x$ by substituting $y$ in equation $1$

$−x−y=−1$

$−x=−1+y$

$x=1-y$

$x=1-1$

$color(blue)(x=0$

How do you solve the following system?: -x -y =-1, x -y = -1−x−y=−1,x−y=−1-x -y =-1, x -y = -1