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How do you solve the following system: $x + y = 16, 3 x + 4 y = - 2$ $x + y = 16, 3x + 4y = -2$ ?

1 Answer

Jun 12, 2018

$x = 66 . y = - 50$ $x=66.y=-50$

Explanation:

Multiplying the first equation by $- 3$ $-3$ and adding to the second
$y = - 50$ $y=-50$
so we get

$x = 16 - (- 50) = 66$ $x=16-(-50)=66$

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