How do you solve the following system?: $- x - y = 2, x - y = - 1$ $-x -y =2, x -y = -1$

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How do you solve the following system?: $- x - y = 2, x - y = - 1$ $-x -y =2, x -y = -1$

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Answer 1 · 2018-04-21T09:02:10

Lettuce solve for $y$ $y$
$1^{s t}$ $1^(st)$ equation
$- x - y = 2$ $-x-y=2$
$- y = 2 + x$ $-y=2+x$
$y = - 2 - x$ $color(red)(y=-2-x$

$2^{n d}$ $2^(nd)$ equation
$x - y = - 1$ $x-y=-1$
We already know $- y$ $-y$
$x + 2 + x = - 1$ $x+2+x=-1$
$2 x = - 1 - 2$ $2x=-1-2$
$2 x = - 3$ $2x=-3$
$x = - \frac{3}{2}$ $x=-3/2$
$x = - 1.5$ $color(red)(x=-1.5$
$y = - 2 - x$ $y=-2-x$
$y = - 2 - 1.5$ $y=-2-1.5$
$y = - 0.5$ $color(red)(y=-0.5$

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How do you solve the following system?: $- x - y = 2, x - y = - 1$ $-x -y =2, x -y = -1$

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Science

Math

Humanities

... and beyond

How do you solve the following system?: −x−y=2,x−y=−1-x -y =2, x -y = -1

1 Answer

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Impact of this question

How do you solve the following system?: $- x - y = 2, x - y = - 1$ $-x -y =2, x -y = -1$