How do you solve the following system?: $y = 2 x - 3, 2 y = 4 x + 3$ $y=2x-3 , 2y=4x+3$

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How do you solve the following system?: $y = 2 x - 3, 2 y = 4 x + 3$ $y=2x-3 , 2y=4x+3$

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Answer 1 · 2018-04-01T09:32:56

$no solution$ $"no solution"$

Explanation:

$consider the 2 equations expressed in slope-intercept form$ $"consider the 2 equations expressed in "color(blue)"slope-intercept form"$

$∙ x y = m x + b$ $•color(white)(x)y=mx+b$

$where m is the slope and b the y-intercept$ $"where m is the slope and b the y-intercept"$

$y = 2 x - 3 \to (1)$ $y=2x-3to(1)$

$y = 2 x + \frac{3}{2} \to (2)$ $y=2x+3/2to(2)$

$both lines have m = 2$ $"both lines have "m=2$

$∙ Parallel lines have equal slopes$ $• " Parallel lines have equal slopes"$

$the 2 lines are therefore parallel and never intersect$ $"the 2 lines are therefore parallel and never intersect"$

$\Rightarrow there is no solution$ $rArr" there is no solution"$
graph{(y-2x+3)(y-2x-3/2)=0 [-10, 10, -5, 5]}

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How do you solve the following system?: $y = 2 x - 3, 2 y = 4 x + 3$ $y=2x-3 , 2y=4x+3$

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

How do you solve the following system?: y=2x−3,2y=4x+3y=2x-3 , 2y=4x+3

1 Answer

Explanation:

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Impact of this question

How do you solve the following system?: $y = 2 x - 3, 2 y = 4 x + 3$ $y=2x-3 , 2y=4x+3$