How do you solve the following system: $y = 3x – 12, 2x – 4y = 8$ ?

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Answer 1 · 2015-12-30T09:54:33

$x=4$ , $y=0$

$color(white)xxy=3x-12,2x-4y=8$

$color(white)xx2x-4y=8<=>y=(x-4)/2$

$=>color(red)(3x-12)=(x-4)/2$
$=>color(blue)(x-4)=(x-4)/2$

$=>x-4=0$
$=>x-4color(green)(+4)=0color(green)(+4)$
$=>x=4$

$=>y=(color(red)4-4)/2$
$=>y=0$

How do you solve the following system: y = 3x – 12, 2x – 4y = 8y = 3x – 12, 2x – 4y = 8?