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How do you solve the following system?: $y = 4 x - 6, y = x - 2$ $y=4x- 6 , y=x-2$

1 Answer

Mar 5, 2016

$x - 2 = 4 x - 6 \to 3 x = 4 \to x = \frac{4}{3}$ $x-2 = 4x-6 ->3x=4 -> x = 4/3$

Explanation:

Use substitution method and equate the two equations then combine like terms and solve for x

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