How do you solve the rational equation #(3a-2)/(2a+2)=3/(a-1)#?
1 Answer
Jan 7, 2016
Multiply both sides by
#a=-1/3# or#a=4#
Explanation:
Multiply both sides by
#(3a-2)(a-1) = 3(2a+2)#
That is:
#3a^2-5a+2 = 6a+6#
Subtract
#3a^2-11a-4 = 0#
Factor this by noticing that
So:
#0 = 3a^2-11a-4#
#= (3a^2-12a) + (a-4)#
#= 3a(a-4)+1(a-4)#
#= (3a+1)(a-4)#
Hence
It remains to check that when we multiplied both sides by
That's OK since