How do you solve the right triangle ABC given A= 40 degrees, C= 70 degrees, a=20?

1 Answer
Jul 25, 2015

29.229.2

Explanation:

Assuming that aa represents the side opposite angle AA and that cc is the side opposite angle CC,
Not drawn to scale!Not drawn to scale!
We apply the rule of sines :

sin(A)/a=sin(C)/csin(A)a=sin(C)c

=>c=(asin(C))/sin(A)=(20*sin(70))/sin(40)~=29c=asin(C)sin(A)=20sin(70)sin(40)29

Good to know :
Larger the angle the longer the side opposite to it.

Angle CC is greater than angle AA, so we predict that side cc will be longer than side aa.