How do you solve the right triangle ABC if a=32m, A=46?

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Answer 1 · 2018-05-06T09:52:46

#C=90^circ#

#B=90^circ-46^circ=44^circ.#

#b = a/tan A approx 30.902#

#c = a/sin A approx 44.485 #

#a=32# m, #A=46^circ. # Let's say #C=90^circ# so #B=90^circ-46^circ=44^circ.#

This is almost an isosceles triangle but it's certainly a right triangle. We have

#tan A = a/b#

#b = a/tan A = 32/{tan 46^circ} approx 30.902#

#sin A = a/c #

#c = a/sin A = 32/{sin 46^circ} approx 44.485 #