How do you solve the right triangle give b=1.83 c=3.35?

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Answer 1 · 2018-04-12T10:29:43

$Case 1 : A Hypotenuse, A_{A} = 3.07$ $"Case 1 : A Hypotenuse, " A_A = 3.07$

$Case 1 : C Hypotenuse, A_{C} = 2.57$ $"Case 1 : C Hypotenuse, " A_C = 2.57$

#"Case 1 : a is hypotenuse"

Applying Pythagoras Theorem,

$Hypotenuse a = \sqrt{b^{2} + c^{2}} = \sqrt{1, 83^{2} + {3.35}^{2}} = 3.82$ $"Hypotenuse " a = sqrt(b^2 + c^2) = sqrt(1,83^2 + 3.35^2) = 3.82$

$"Area of Right " Delta = (1/2) * b * c = (1/2) * 1.83 * 3.35 ~~ 3.07$

#"Case 2 : c is hypotenuse"

Applying Pythagoras Theorem,

$a = sqrt(c^2 - b^2) = sqrt(3.35^2 - 1.83^2) = 2.81$

$"Area of Right " Delta = (1/2) * a * b = (1/2) * 2.81 * 1.83 ~~ 2.57$