How do you solve the simultaneous equations # 5c + 4d = 23# and #3c - 5d = -1#?

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Answer 1 · 2018-04-18T11:44:19

Solution : #c=3 , d=2#

#5 c+4 d=23 (1) , 3 c -5 d= -1 (2)# Multiplying equation (1) by

#3# and equation (2) by #5# we get,

#15 c+12 d=69 (3) , 15 c -25 d= -5 (4)# Subtracting equation

(4) from equation (3) we get, #37 d=74 :. d =74/37=2#

Putting #d=2# in equation (1) we get, #5 c + 4 *2 =23# or

#5 c= 23 -8 or 5 c = 15 or c = 15/5 =3 #

Solution : #c=3 , d=2# [Ans]