Question

How do you solve the system `14x+5y=31, 2x-3y=-29`?

Answer 1

`y=9,x=-1`

Explanation:

`(1) 14x+5y=31`
`(2) 2x-3y=-29`

Let's eliminate the y's the isolate the x and solve for x.
To do this, multiply (1) by 3, and (2) by 5.

`(1) 42x+15y=93`
`(2) 10x-15y=-145`

(1)+(2) to eliminate y.

This leaves us with:

`52x=-52`

therefore `x=-1`

Substitute this back into one of the original equation to get:

`-14+5y=31`
Solve for y,
`y=9`