Question

How do you solve the system 2x+3y=19 , 8x-3y=-4?

Answer 1

`y=16/3`
`x=3/2`

Explanation:

`2x+3y = 19` |
`8x-3y=-4`
First I added the two functions together canceling out -3y and 3y. we now have a function that resembles `10x = 15`
dividing by 10 on both sides x= 3/2

Now multiply the first function by -4 equivalent to the original function
`-8x-12y = -76` |
`8x-3y=-4`
Add the functions together
`-15y = -80`
divide by -15 canceling out the negatives leaving y = 80/15 or 16/3