How do you solve the system $2 x + y = 2 - x$ $2x + y = 2 - x$ and $x + 2 y = 2 + x$ $x + 2y = 2+x$ ?

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Answer 1 · 2018-06-25T08:29:12

$y = 1, x = \frac{1}{3}$ $y=1 , x=1/3$

$2 x + y = 2 - x$ $2x+y=2-x$ and $x + 2 y = 2 + x$ $x+2y=2+x$

Notice in the second equation you can cancel an $x$ $x$ on both sides.

$cancel(x)+2y=2+cancel(x)$

Therefore $y=1$ subbing this into equation 1 gives the result

$2x+1=2-x rarr 2x+x=2-1 rarr 3x=1 rarr x=1/3$

How do you solve the system 2x + y = 2 - x2x+y=2−x2x + y = 2 - x and x + 2y = 2+xx+2y=2+xx + 2y = 2+x?