How do you solve the system #-2x+y=8 and y=-3x-2#?
2 Answers
Jul 9, 2018
Explanation:
Plugging the second equation
adding
Jul 9, 2018
Explanation:
#-2x+y=8to(1)#
#y=-3x-2to(2)#
#"equation "(2)" expresses y in terms of "x#
#"substitute "y=-3x-2" into equation "(1)#
#-2x-3x-2=8#
#-5x-2=8#
#"add 2 to both sides"#
#-5x=8+2=10#
#"divide both sides by "-5#
#x=10/(-5)rArrx=-2#
#"substitute "x=-2" into equation "(2)#
#y=6-2=4#
#"the point of intersection "=(-2,4)#
graph{(y+3x+2)(y-2x-8)=0 [-10, 10, -5, 5]}