How do you solve the system #2x - y = 8#, #x + 2y = 9#?

1 Answer
Jan 31, 2016

Solving simultaneous equations involves using algebra to eliminate one variable and solve for the other, then using that one to find the value of the other. The solution is #x=3.33, y=2.33#.

Explanation:

Let's label our two equations as (1) and (2) to make them easy to refer to:

#2x-y=8# (1)
#x+2y=9# (2)

Multiply (2) by 2:

#2x+4y=18#

Subtract (1) from this equation:

#2x+4y=18# minus
#2x-y=8#

Yields:

#3y=10#

This is an equation in only one variable, so we can solve it:

#y=10/3 or 3.33#

Substitute this in either (1) or (2) to find #x#. I'll use (2) because it's simpler:

#x+2(10/3)=9#

Rearranging:

#x=9-20/3 = 2.33#

The solution is #x=3.33, y=2.33#.

(you can check this by substituting these values into either of the two original equations and ensuring that the sides are equal to each other)