How do you solve the system 3x+2y=19 and 2x-3y=-9 by substitution? Algebra Linear Inequalities and Absolute Value Linear Inequalities in Two Variables 1 Answer Nghi N. May 24, 2015 3x + 2y = 19 -> 3x = 19 - 2y -> x = (19 - 2y)/3 2x - 3y = -9 -> (2/3).(19 - 2y) - 3y = -9 38 - 4y - 9y = -27 -> -13y = -27 - 38 = - 65 y = 65/13 = 5 x = (19 - 10)/3 = 9/3 = 3 Check: 3(3) + 2(5) = 19. OK Answer link Related questions How do you graph linear inequalities in two variables? How many solutions does a linear inequality in two variables have? How do you know if you need to shade above or below the line? What is the difference between graphing x=1 on a coordinate plane and on a number line? How do you graph y \le 4x+3? How do you graph 3x-4y \ge 12? How do you graph y+5 \le -4x+10? How do you graph the linear inequality -2x - 5y<10? How do you graph the inequality –3x – 4y<=12? How do you graph the region 3x-4y>= -12? See all questions in Linear Inequalities in Two Variables Impact of this question 5662 views around the world You can reuse this answer Creative Commons License