How do you solve the system 3x+2y=19 and 2x-3y=-9 by substitution?

1 Answer
May 24, 2015

3x + 2y = 19 -> 3x = 19 - 2y -> x = (19 - 2y)/3

2x - 3y = -9 -> (2/3).(19 - 2y) - 3y = -9

38 - 4y - 9y = -27 -> -13y = -27 - 38 = - 65

y = 65/13 = 5

x = (19 - 10)/3 = 9/3 = 3

Check: 3(3) + 2(5) = 19. OK