How do you solve the system $- 6 x - 2 y + 2 z = - 8$ $-6x-2y+2z=-8$ , $3 x - 2 y - 4 z = 8$ $3x-2y-4z=8$ , and $6 x - 2 y - 6 z = - 18$ $6x-2y-6z=-18$ ?

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How do you solve the system $- 6 x - 2 y + 2 z = - 8$ $-6x-2y+2z=-8$ , $3 x - 2 y - 4 z = 8$ $3x-2y-4z=8$ , and $6 x - 2 y - 6 z = - 18$ $6x-2y-6z=-18$ ?

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Answer 1 · 2018-05-28T19:56:48

I'm not sure you can...

Explanation:

I did a quick calculation on the matrix and it appears that the determinant is zero. You need to invert the matrix to solve this system and if the det = 0, I don't think it can be done...

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How do you solve the system $- 6 x - 2 y + 2 z = - 8$ $-6x-2y+2z=-8$ , $3 x - 2 y - 4 z = 8$ $3x-2y-4z=8$ , and $6 x - 2 y - 6 z = - 18$ $6x-2y-6z=-18$ ?

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How do you solve the system −6x−2y+2z=−8-6x-2y+2z=-8, 3x−2y−4z=83x-2y-4z=8, and 6x−2y−6z=−186x-2y-6z=-18?

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How do you solve the system $- 6 x - 2 y + 2 z = - 8$ $-6x-2y+2z=-8$ , $3 x - 2 y - 4 z = 8$ $3x-2y-4z=8$ , and $6 x - 2 y - 6 z = - 18$ $6x-2y-6z=-18$ ?