How do you solve the system #7x-3y=19 #, #5x+2y=-11#?

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Answer 1 · 2016-04-17T07:58:09

#x=5/29# and #y=-5 27/29#

The two equations are

#7x-3y=19# ............(A) and

#5x+2y=-11# ...........(B)

Now multiplying (A) by #2# and (B) by #3#, we get

#14x-6y=38# ............(C) and

#15x+6y=-33# ...........(D)

Adding (c) and (D), we get

#29x=5# or #x=5/29#. Now putting this in (B)

#(5xx5)/29+2y=-11# or #25/29+2y=-11# or

#2y=-25/29-11=-25/29-(11xx29)/29=(-25-319)/29=-344/29#

#y=-344/29xx1/2=-172/29==(5XX29+27)/29=-5 27/29#