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How do you solve the system of equations $3 x - 2 y = 4$ $3x - 2y = 4$ and $2 x + 3 y = - 6$ $2x + 3y = - 6$ ?

1 Answer

May 30, 2018

$x = 0$ $x=0$ and $y = - 2$ $y=-2$

Explanation:

Multiplying the first equation by $3$ $3$ and the second one by $2$ $2$
and adding both we get

$13 x = 0$ $13x=0$ so $x = 0$ $x=0$
With $x = 0$ $x=0$ we get

$y = - 2$ $y=-2$

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